[tex]3a)\\\\(-4x+8):4=\frac{-4x}{4}+\frac{8}{4}=-x+2\\\\b)\\\\\frac{5x+10y}{5}=\frac{5x}{5}+\frac{10y}{5}=x+2y[/tex]
[tex]c)\\\\(6p^2-8pr):(-2)=\frac{6p^2}{-2}-\frac{8pr}{ -2 }=-3p^2+4pr\\\\d)\\\\\frac{3x-6y+1}{-3}=\frac{3x}{-3}- \frac{6y}{-3}+\frac{1}{-3}=-x+2y-\frac{1}{ 3}[/tex]
[tex]e)\\\\(x^2+x-1):(-\frac{1}{6})=(x^2+x-1)*( -6)=-6x^2-6x+6\\\\f)\\\\\frac{2,5x^2-0,5x+1}{5}=\frac{2,5x^2 }{5}- \frac{ 0,5x }{5}+\frac{ 1}{5}= 0,5x^2-0,1x+\frac{1}{5}[/tex]
[tex]4a)\\\\2x+5-\frac{3x-12}{3}=2x+5-(\frac{3x}{3}-\frac{12}{3})=2x+5-x+4=x+9[/tex]
[tex]b)\\\\ \frac{12x+16}{4}-\frac{10x+15}{5}=\frac{12x}{4}+\frac{16}{4}-(\frac{10x}{5}+\frac{15}{5})=3x+4 -(2x+3)=3x+4 - 2x-3=x+1[/tex]
[tex]c)\\\\ \frac{9-6x}{3}-\frac{21-14x}{7}=\frac{ 9}{3}- \frac{ 6x}{3}-(\frac{21}{7}-\frac{14x}{7})= 3-2x-(3-2x)= 3-2x-3+2x=0[/tex]
[tex]d)\\\\ \frac{4x-8}{2}-3*\frac{10x-50}{5}=\frac{ 4x}{2}- \frac{ 8}{2}-3*(\frac{10x}{5}-\frac{50}{5})= 2x-4-3*(2x-10)=\\\\=2x-4-6x+30=-4x+26[/tex]
