Odpowiedź:
[tex]\begin{cases}5(3-\frac{1}{4}x)\leq 12\\0,3x\geq x-0,2-\frac{2}{3}x\end{cases}\\\\\\\begin{cases}15-\frac{5}{4}x\leq 12\\0,3x-x+\frac{2}{3}x\geq -0,2\end{cases}\\\\\\\begin{cases}-\frac{5}{4}x\leq 12-15\\\frac{3}{10}x-x+\frac{2}{3}x\geq -\frac{1}{5}\ \ /\cdot30\end{cases}\\\\\\\begin{cases}-\frac{5}{4}x\leq -3\ \ /\cdot4\\9x-30x+20x\geq -6\end{cases}\\\\\\\begin{cases}-5x\leq -12\ \ /:(-5)\\-x\geq -6\cdot(-1)\end{cases}\\\\\\\begin{cases}x\geq \frac{12}{5}\\x\leq 6\end{cases}[/tex]
[tex]x\in\langle\frac{12}{5},6\rangle[/tex]
