Odpowiedź:
1. F
2. P
Wyjaśnienie.
ad.1.
[tex]dla \ \ x = -2 \ \ i \ \ y = 3\\\\3xy^{2}-x^{2} = 2\cdot(-2)\cdot3^{2}-(-2)^{2} = -6\cdot9 -4 = -54-4 = -58 \neq -50[/tex]
ad.2.
[tex]dla \ \ a = 4 \ \ i \ \ b = -1\\\\\\\frac{2(a^{2}+b)}{3} = \frac{2(4^{2}-1)}{3}=\frac{2(16-1)}{3} = \frac{2\cdot15}{3} = 2\cdot5 = 10\\\\\\\frac{a(8+b)}{2}-4 = \frac{4(8-1)}{2}-4 = 2\cdot7-4 = 14-4 = 10[/tex]
