Odpowiedź:
[tex]f)\ \ 3\frac{3}{4}:\frac{2}{3}:8+\frac{1}{\not8_{1}}\cdot\frac{\not16^2}{5}=\frac{15}{4}\cdot\frac{3}{2}\cdot\frac{1}{8}+\frac{2}{5}=\frac{45}{64}+\frac{2}{5}=\frac{225}{320}+\frac{128}{320}=\frac{353}{320}=1\frac{33}{320}[/tex]
[tex]g)\ \ (1\frac{1}{2})^2-(\frac{2}{3})^2:2=(\frac{3}{2})^2-\frac{\not4^2}{9}\cdot\frac{1}{\not2_{1}}=\frac{9}{4}-\frac{2}{9}=\frac{81}{36}-\frac{8}{36}=\frac{73}{36}=2\frac{1}{36}\\\\\\h)\ \ (1\frac{2}{3})^2+\frac{5}{18}:\frac{1}{2}=(\frac{5}{3})^2+\frac{5}{\not18_{9}}\cdot\not2^1=\frac{25}{9}+\frac{5}{9}=\frac{30}{9}=3\frac{3}{9}=3\frac{1}{3}[/tex]
[tex]i)\ \ \dfrac{2\cdot2\frac{2}{3}}{3\frac{5}{6}+3\frac{5}{12}\cdot2}=\dfrac{2\cdot\frac{8}{3}}{3\frac{5}{6}+\frac{41}{\not12_{6}}\cdot\not2^1}=\dfrac{\frac{16}{3}}{\frac{23}{6}+\frac{41}{6}}=\dfrac{\frac{16}{3}}{\frac{64}{6}}=\frac{16}{3}:\frac{64}{6}=\frac{16}{3}:\frac{32}{3}=\\\\\\=\frac{\not16^1}{\not3_{1}}\cdot\frac{\not3^1}{\not32_{2}}=\frac{1}{2}[/tex]
[tex]j)\ \ \dfrac{3\frac{1}{6}-1\frac{1}{2}}{\frac{1}{6}+\frac{1}{2}:3}=\dfrac{\frac{19}{6}-\frac{3}{2}}{\frac{1}{6}+\frac{1}{2} \cdot\frac{1}{3}}=\dfrac{\frac{19}{6}-\frac{9}{6}}{\frac{1}{6}+\frac{1}{6}}=\dfrac{\frac{10}{6}}{\frac{2}{6}}=\dfrac{\frac{5}{3}}{\frac{1}{3}}=\frac{5}{3}:\frac{1}{3}=\frac{5}{\not3}\cdot\not3=5[/tex]
