Odpowiedź :
[tex]2a\cdot(5a+2b-3) = 2a\cdot5a + 2a\cdot2b - 2a\cdot3 = 10a^{2}+4ab-6a\\\\\\3(2m-4) + 5(3-4m) = 3\cdot2m - 3\cdot4 + 5\cdot3 -5\csot4m = 6m-12+15-20m = 3-14m[/tex]
[tex]2a\cdot(5a+2b-3) = 2a\cdot5a + 2a\cdot2b - 2a\cdot3 = 10a^{2}+4ab-6a\\\\\\3(2m-4) + 5(3-4m) = 3\cdot2m - 3\cdot4 + 5\cdot3 -5\csot4m = 6m-12+15-20m = 3-14m[/tex]