Odpowiedź :
[tex]Dane:\\F_1 = 250 \ N\\S_1 = 25 \ cm^{2}\\F_2 = 500 \ N\\Szukane:\\S_2 = ?\\\\Z \ prawa \ Pascala\\\\\frac{F_1}{S_1} = \frac{F_2}{S_2}\\\\F_1\cdot S_2 = F_2\cdot S_1 \ \ /:F_1\\\\S_2 = \frac{F_2}{F_1}\cdot S_1\\\\S_2 = \frac{500 \ N}{250 \ N}\cdot25 \ cm^{2}\\\\\boxed{S_2 = 50 \ cm^{2}}[/tex]
Odp. Pole powierzchni dużego tłoka S₂ = 50 cm².