Odpowiedź :
[tex]Dane:\\m = 4 \ dag =40 \ g\\V = 20 \ cm^{3}}\\Szukane:\\d = ?\\\\d = \frac{m}{V}\\\\d = \frac{40 \ g}{20 \ cm^{3}}\\\\\boxed{d = 2\frac{g}{cm^{3}}=2000\frac{kg}{m^{3}}}[/tex]
[tex]Dane:\\m = 4 \ dag =40 \ g\\V = 20 \ cm^{3}}\\Szukane:\\d = ?\\\\d = \frac{m}{V}\\\\d = \frac{40 \ g}{20 \ cm^{3}}\\\\\boxed{d = 2\frac{g}{cm^{3}}=2000\frac{kg}{m^{3}}}[/tex]