Odpowiedź:
[tex]\huge\boxed{\boxed{a)=1\frac{7}{40}}}[/tex]
[tex]\huge\boxed{\boxed{b)=4\frac{9}{32}}}[/tex]
[tex]\huge\boxed{\boxed{c)=3\frac{17}{18}}}[/tex]
[tex]\huge\boxed{\boxed{d)=1\frac{1}{20}}}[/tex]
Szczegółowe wyjaśnienie:
Podpunkt a)
[tex](3\frac{3}{4}+2\frac{1}{8}):5=(3\frac{3\cdot2}{4\cdot2}+2\frac{1}{8}):5=(3\frac{6}{8}+2\frac{1}{8}):5=\\\\=5\frac{7}{8}:5=\frac{5\cdot8+7}{8}:5=\frac{40+7}{8}:5=\frac{47}{5}:5=\frac{47}{8}\cdot\frac{1}{5}=\frac{47}{40}=1\frac{7}{40}[/tex]
Podpunkt b)
[tex]6\frac{1}{8}:4+2\frac{3}{4}=\frac{6\cdot8+1}{8}:4+2\frac{3}{4}=\frac{48+1}{8}:4+2\frac{3}{4}=\\\\=\frac{49}{8}:4+2\frac{3}{4}=\frac{49}{8}\cdot\frac{1}{4}+2\frac{3}{4}=\frac{49}{32}+2\frac{3}{4}=1\frac{17}{32}+2\frac{3}{4}=\\\\=1\frac{17}{32}+2\frac{3\cdot8}{4\cdot8}=1\frac{17}{32}+2\frac{24}{32}=3\frac{41}{32}=4\frac{9}{32}[/tex]
Podpunkt c)
[tex]3\frac{1}{6}+2\frac{1}{3}:3=3\frac{1}{6}+\frac{2\cdot3+1}{3}:3=3\frac{1}{6}+\frac{6+1}{3}:3=3\frac{1}{6}+\frac{7}{3}:3=\\\\=3\frac{1}{6}+\frac{7}{3}\cdot\frac{1}{3}=3\frac{1}{6}+\frac{7}{9}=3\frac{1\cdot3}{6\cdot3}+\frac{7\cdot2}{9\cdot2}=3\frac{3}{18}+\frac{14}{18}=3\frac{17}{18}[/tex]
Podpunkt d)
[tex](4\frac{3}{5}-2\frac{1}{2}):2=(4\frac{3\cdot2}{5\cdot2}-2\frac{1\cdot5}{2\cdot5}):2=(4\frac{6}{10}-2\frac{5}{10}):2=2\frac{1}{10}:2=\\\\=\frac{2\cdot10+1}{10}:2=\frac{20+1}{10}:2=\frac{21}{10}:2=\frac{21}{10}\cdot\frac{1}{2}=\frac{21}{20}=1\frac{1}{20}[/tex]
