Odpowiedź:
[tex]e)\\\\2x(x-1)=2(x-1)(x+3)\\\\2x^2-2x=2(x^2+3x-x-3)\\\\2x^2-2x=2(x^2+2x-3)\\\\2x^2-2x=2x^2+4x-6\\\\2x^2-2x-2x^2-4x=-6\\\\-6x=-6\ \ /:(-6)\\\\x=1\\\\\\f)\\\\(3x+2)(2x+1)=(6x-3)(x+1)\\\\6x^2+3x+4x+2=6x^2+6x-3x-3\\\\6x^2+7x+2=6x^2+3x-3\\\\6x^2+7x-6x^2-3x=-3-2\\\\4x=-5\ \ /:4\\\\x=-\frac{5}{4}\\\\x=-1\frac{1}{4}[/tex]
