[tex]2x(x+4)>3(x^{2} +\frac{7}{3})\\2x^{2} +8x>3x^{2} +7\\2x^{2}-3x^{2}+8x-7>0\\-x^{2}+8x-7>0\\[/tex]
[tex]8^{2} -4*(-1)*(-7) = 64-28 = 36\\\sqrt{36} = 6\\x_{1} = \frac{-8+6}{-2} = \frac{-2}{-2} = 1\\x_{2} = \frac{-8-6}{-2} = \frac{-14}{-2} = 7\\[/tex]
x∈(1;7)
