Odpowiedź i szczegółowe wyjaśnienie:
[tex]c)\ \sqrt[3]{16}\cdot\sqrt[3]{32}=\sqrt[3]{2^4}\cdot\sqrt[3]{2^5}=\sqrt[3]{2^4\cdot2^5}=\sqrt[3]{2^9}=(2^9)^\frac13=2^3=8\\\\\\d)\ \dfrac{\sqrt[3]{-32}}{\sqrt[3]{4}}=\sqrt[3]{\dfrac{-32}{4}}=\sqrt[3]{-8}}=\sqrt[3]{(-2)^3}=-2\\\\\\e)\ \dfrac{\sqrt[3]{54}}{\sqrt[3]{-2}}=\sqrt[3]{\dfrac{54}{-2}}=\sqrt[3]{-27}=\sqrt[3]{(-3)^3}=-3\\\\\\[/tex]
[tex]f)\ \dfrac{\sqrt[3]{750}}{\sqrt[3]{48}}=\dfrac{\sqrt[3]{125\cdot6}}{\sqrt[3]{8\cdot6}}=\dfrac{\sqrt[3]{5^3\cdot6}}{\sqrt[3]{2^3\cdot6}}=\dfrac{\sqrt[3]{5^3}\cdot\sqrt[3]{6}}{\sqrt[3]{2^3}\cdot\sqrt[3]6}=\dfrac{5}{2}[/tex]
