Odpowiedź:
I=q/t
1)
t=3min=180s
q=600C
I=600C/180s
I=3,3A
2)
t=0,5h=1800s
I=20A
q=I*t
q=20A*1800s=36000C=36kC
3)
q=4kC=4000C
I=0,002MA=2kA=2000A
t=q/I
t=4000C/2000A
t=2s
