Odpowiedź:
[tex]\dfrac{6}{\sqrt{3}}=\dfrac{6}{\sqrt{3}}\cdot\dfrac{\sqrt{3}}{\sqrt{3}}=\dfrac{\not6^2\sqrt{3}}{\not3_{1}}=2\sqrt{3}\\\\\\2^5:3^2=\frac{2^5}{3^2}=\frac{32}{9}=3\frac{5}{9}\\\\2^3:3^3=\frac{2^3}{3^3}=\frac{8}{27}\\\\10^2:5^2=(10:5)^2=2^2=4[/tex]
