Odpowiedź:
Zadanie 59
a) [tex]3\frac{3}{5} + \frac{6}{10} = 3\frac{6}{10} + \frac{6}{10} = 3\frac{12}{10} = 4\frac{2}{10}\\[/tex]
f) [tex]3\frac{5}{6} + 2\frac{3}{8} = 3\frac{20}{24} + 2\frac{9}{24} = 5\frac{29}{24} = 6\frac{5}{24}[/tex]
Zadanie 60
e) [tex]3\frac{5}{8} - 2\frac{5}{6} = 3\frac{15}{24} - 2\frac{20}{24} = \frac{87}{24} - \frac{68}{24} = \frac{19}{24}[/tex]
f) [tex]3\frac{5}{6} - 2\frac{4}{9} = 3\frac{30}{36} - 2\frac{16}{36} = \frac{138}{36} - \frac{88}{36} = \frac{50}{36} = 1\frac{14}{36} = 1\frac{7}{18}[/tex]
Szczegółowe wyjaśnienie:
