[tex]\sqrt{\dfrac{9}{25}}\cdot\sqrt{\dfrac{25}{36}}+(\sqrt{361})^{2}-4\cdot\sqrt{0,49}\cdot\sqrt{100}=\\\\=\sqrt{\dfrac{3^{2}}{5^{2}}}\cdot\sqrt{\dfrac{5^{2}}{6^{2}}}+361-4\cdot\sqrt{0,49\cdot100}=\\\\=\dfrac{3}{\not5}\cdot\dfrac{\not5}{6}+361-4\cdot\sqrt{49}=\\\\=\dfrac{3}{6}+361-4\cdot\sqrt{7^{2}}=\\\\=\dfrac{1}{2}+361-4\cdot7=\\\\=\dfrac{1}{2}+361-28=\\\\=\boxed{333\dfrac{1}{2}}[/tex]
