[tex]2^{\frac{1}{2}}\cdot50^{\frac{1}{2}} - 2^{\frac{1}{5}}\cdot16^{\frac{1}{5}} = (2\cdot50)^{\frac{1}{2}}-(2\cdot16)^{\frac{1}{5}} = 100^{\frac{1}{2}} -32^{\frac{1}{5}} = (10^{2})^{\frac{1}{2}}-(2^{5})^{\frac{1}{5}}=\\\\=10^{2\cdot\frac{1}{2}}-2^{5\cdot\frac{1}{5}} = 10^{1}-2^{1} = 10-2 = 8[/tex]
