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[tex]2\frac{3}{5}-\frac{7}{10}=2\frac{3\cdot2}{5\cdot2}-\frac{7}{10}=2\frac{6}{10}-\frac{7}{10}=1\frac{16}{10}-\frac{7}{10}=1\frac{9}{10}\\\\1\frac{1}{6}-\frac{7}{9}=1\frac{1\cdot3}{6\cdot3}-\frac{7\cdot2}{9\cdot2}=1\frac{3}{18}-\frac{14}{18}=\frac{21}{18}-\frac{14}{18}=\frac{7}{18}[/tex]
