Odpowiedź:
Szczegółowe wyjaśnienie:
x+y=56
x-y=16
+
2x=72/:2
x=36
36-y=16
-y=-20/:(-1)
y=20
[tex]a, ~~b ~~- szukane ~~liczby~~zal.~~a>b\\\\z ~~tresci~~zadania~~wiemy:\\\\a+b=56~~oraz~~a-b=16~~\Rightarrow mamy~~uklad~~rownan~~(sa~~dwie~~niewiadome)\\\\\left \{ {{a+b=56} \atop {a-b=16}} \right. \\\\\left \{ {{a=56-b} \atop {56-b-b=16}} \right. \\\\\left \{ {{a=56-b} \atop {-2b=16-56}} \right. \\\\\left \{ {{a=56-b} \atop {-2b=-40}~~\mid\div (-2)} \right. \\\\\left \{ {{a=56-b} \atop {b=20}} \right. \\\\\left \{ {{b=20} \atop {a=56-20}} \right. \\\\[/tex]
[tex]\left \{ {{b=20} \atop {a=36}} \right.[/tex]
[tex]Sprawdzam~~~\\\\a+b=56~~\land~~a=36~~\land~~b=20\\\\36+20=56\\\\56=56\\\\L=P\\\\\\a-b=56~~\land~~a=36~~\land~~b=20\\\\36-20=16\\\\16=16\\\\L=P\\\\\\Odp:~~Szukane~~ liczby :~~36~~oraz ~~20.[/tex]
