Odpowiedź:
masa cząsteczkowa
m8H2S= 16× 1u+ 8+ 32u= 16u+ 256u= 272u
m4Ba(OH)2= 4× 137u+ 8× 16u+ 8× 1u÷548u+ 128u+ 8u= 684u
m3CaCO3= 3+ 40u+ 3× 12u+ 9× 16u= 120u+ 36u+ 144u= 300u
masa molowa
M8H2S= 16× 1g/mol+ 8+ 32g/mol = 16g/mol + 256g/mol = 272 g/mol
M4Ba(OH)2= 4× 137g/mol + 8× 16g/mol + 8× 1g/mol= 548g/mol + 128g/mol + 8g/mol = 684 g/mol
M3CaCO3= 3+ 40g/mol + 3× 12g/mol + 9× 16g/mol = 120g/mol + 36g/mol + 144g/mol = 300g/mol
Wyjaśnienie:
