Odpowiedź i szczegółowe wyjaśnienie:
[tex]\dfrac{(4\frac23-3,25):(3\frac13-2,5)}{(3\frac23+1,8)\cdot\frac5{41}}:\dfrac{17}{4}=\\\\\\=\dfrac{(4\frac23-3\frac14):(3\frac13-2\frac12)}{(3\frac23+1\frac45)\cdot\frac{5}{41}}\cdot\dfrac{4}{17}=\\\\\\=\dfrac{(4\frac{8}{12}-3\frac{3}{12}):(3\frac{2}{6}-2\frac{3}{6})}{(3\frac{10}{15}+1\frac{12}{15})\cdot\frac{5}{41}}\cdot\dfrac{4}{17}=\\\\\\=\dfrac{1\frac{5}{12}:(\frac{20}{6}-\frac{15}{6})}{4\frac{22}{15}\cdot\frac{5}{41}}\cdot\dfrac{4}{17}=\\\\\\[/tex]
[tex]=\dfrac{\frac{17}{12}:\frac{5}{6}}{\frac{82}{15}\cdot\frac{5}{41}}\cdot\dfrac{4}{17}=\\\\\\=\dfrac{\frac{17}{12}\cdot\frac65}{\frac{82}{15}\cdot\frac{5}{41}}\cdot\dfrac{4}{17}=\\\\\\=\dfrac{\frac{17}{10}}{\frac{41\cdot2}{3\cdot5}\cdot\frac{5}{41}}\cdot\dfrac{4}{17}=\\\\\\=\dfrac{\frac{17}{10}\cdot\frac{4}{17}}{\frac23}=\\\\\\=\dfrac{\frac4{10}}{\frac23}=\dfrac2{5}\cdot\dfrac{3}{2}=\dfrac35[/tex]
