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[tex]2(3a-4b+6)=2\cdot3a-2\cdot4b+2\cdot6=\boxed{6a-8b+12}\\\\\\\frac{1}{2}xy(4xy-8x+6y-10)=\frac{1}{2}xy\cdot4xy-\frac{1}{2}xy\cdot8x+\frac{1}{2}xy\cdot6y-\frac{1}{2}xy\cdot10=\\\\=\frac{4}{2}x^2y^2-\frac{8}{2}x^2y+\frac{6}{2}xy^2-\frac{10}{2}xy=\boxed{2x^2y^2-4x^2y+3xy^2-5xy}[/tex]
