Odpowiedź:
[tex]d)\\\\\frac{3x+1}{4}-\frac{6-2x}{5}>-\frac{1}{20}-\frac{x-1}{2}\ \ |\cdot20\\\\5(3x+1)-4(6-2x)>-1-10(x-1)\\\\15x+5-24+8x>-1-10x+10\\\\23x-19>9-10x\\\\23x+10x>9+19\\\\33x>28\ \ |:33\\\\x>\frac{28}{33}\\\\x\in(\frac{28}{33},+\infty)\\\\\\e)\\\\-\frac{1}{6}x-\frac{2x-5}{4}\geq 3-\frac{8x-3}{3}\ \ |\cdot12\\\\-2x-3(2x-5)\geq 36-4(8x-3)\\\\-2x-6x+15\geq 36-32x+12\\\\-8x+15\geq 48-32x\\\\-8x+32x\geq 48-15\\\\24x\geq 33\ \ |:24\\\\x\geq \frac{33}{24}\\\\x\geq \frac{11}{8}\\\\x\geq 1\frac{3}{8}[/tex]
[tex]x\in\langle1\frac{3}{8},+\infty)\\\\\\f)\\\\\frac{x-1}{3}-\frac{2x-1}{6}<\frac{1}{2}-\frac{x-3}{5}\ \ |\cdot30\\\\10(x-1)-5(2x-1)<15-6(x-3)\\\\10x-10-10x+5<15-6x+18\\\\-5<33-6x\\\\6x<33+5\\\\6x<38\ \ |:6\\\\x<\frac{38}{6}\\\\x<\frac{19}{3}\\\\x<6\frac{1}{3}\\\\x\in(-\infty,6\frac{1}{3})[/tex]
