Odpowiedź :
Odpowiedź:
[tex] \sqrt{50} + \sqrt{72} - \sqrt{242} = \sqrt{25 \times 2} + \sqrt{36 \times 2} - \sqrt{121 \times 2} = 5 \sqrt{2} + 6 \sqrt{2} - 11 \sqrt{2} = 11 \sqrt{2} - 11 \sqrt{2} = 0[/tex]
Odpowiedź:
[tex] \sqrt{50} + \sqrt{72} - \sqrt{242} = \sqrt{25 \times 2} + \sqrt{36 \times 2} - \sqrt{121 \times 2} = 5 \sqrt{2} + 6 \sqrt{2} - 11 \sqrt{2} = 11 \sqrt{2} - 11 \sqrt{2} = 0[/tex]