Odpowiedź do zadania:
[tex]a) (\sqrt{3} + 1)(2\sqrt{3} - 2) = \sqrt{3} *2\sqrt{3} +\sqrt{3} *(-2)+1*2\sqrt{3} +1*(-2)= 6 + (-2\sqrt{3}) + 2\sqrt{3} +(-2) = 4[/tex]
[tex]b) (\sqrt{2} + 3) (\sqrt{5} + 1)=\sqrt{2} * \sqrt{5} + \sqrt{2} * 1+3*\sqrt{5} + 3 * 1= \sqrt{10} +\sqrt{2} +3\sqrt{5} + 3[/tex]
[tex]c) (\sqrt{2} + 1)(5-2\sqrt{2} )= \sqrt{2} * 5 + \sqrt{2} * 2\sqrt{2} + 1 * 5 + 1*(-2\sqrt{2}) = 5\sqrt{2} + 4 + 5 + (-2\sqrt{2}) = 3\sqrt{2} + 9[/tex]
[tex]d) (2 +\sqrt{2})(2\sqrt{2} + 3) = 2 * 2\sqrt{2} + 2 * 3+ \sqrt{2} * 2\sqrt{2} + \sqrt{2} * 3 = 4\sqrt{2} + 6 + 4 + \sqrt{6} = 4\sqrt{2} + 10 +\sqrt{6}[/tex]
Smacznej herbatki, pozdrawiam <3
