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[tex]\sqrt9+\sqrt{16}+\sqrt{25}=\sqrt{3^2}+\sqrt{4^2}+\sqrt{5^2}=3+4+5=\boxed{12}\\\\15+2(\sqrt5)^2+\sqrt0=15+2\cdot5+\sqrt{0^2}=15+10+0=\boxed{25}\\\\6\sqrt{0,04}-0,3\sqrt{25}=6\sqrt{0,2^2}-0,3\sqrt{5^2}=6\cdot0,2-0,3\cdot5=1,2-1,5=\boxed{-0,3}\\\\\sqrt{225}+\sqrt{16^2}-\sqrt{81}=\sqrt{15^2}+16-\sqrt{9^2}=15+16-9=31-9=\boxed{22}[/tex]
