Odpowiedź:
D
a. [tex]sin^2\alpha+cos^2\alpha = 1\\sin^245^o+cos^245^o = 1[/tex]
b.[tex]\frac{1}{cot^345^o}= \frac{1}{1^3} = 1[/tex]
c. [tex]tg\alpha*ctg\alpha = 1\\tg60^o * ctg60^o = 1[/tex]
d.[tex]tg60^o*cot30^o = \sqrt{3}* \sqrt{3} = 3[/tex]
