[tex](\frac{1}{2}x+\frac{1}{3}x-\frac{1}{4}x)*\frac{6}{7}=1\ \ |*7\\\\ \not{6}^3 *\frac{1}{\not{2}^1 }x+ \not{6}^2 *\frac{1}{\not{3}^1 } x- \not{6}^3 *\frac{1}{\not{4}^2 }x =7\\\\3x+2x-\frac{3}{2}x=7\ \ |*2\\\\6x+4x-3x=14\\\\7x=14\ \ |:7\\\\x=\frac{14}{7}=2[/tex]
