Odpowiedź :
Cześć!
c)
[tex](5x-y)(2y-x)-11xy=\\\\=10xy-5x^2-2y^2+xy-11xy=\\\\=-5x^2-2y^2+10xy+xy-11xy=\boxed{-5x^2-2y^2}[/tex]
d)
[tex](4a-1)(2b+2)+2b(1-2a)=\\\\=8ab+8a-2b-2+2b-4ab=\\\\=8a-2b+2b+8ab-4ab-2=\boxed{8a+4ab-2}[/tex]
Cześć!
c)
[tex](5x-y)(2y-x)-11xy=\\\\=10xy-5x^2-2y^2+xy-11xy=\\\\=-5x^2-2y^2+10xy+xy-11xy=\boxed{-5x^2-2y^2}[/tex]
d)
[tex](4a-1)(2b+2)+2b(1-2a)=\\\\=8ab+8a-2b-2+2b-4ab=\\\\=8a-2b+2b+8ab-4ab-2=\boxed{8a+4ab-2}[/tex]