Odpowiedź:
[tex](\sqrt{3}-\sqrt{2}+\sqrt{7})(\sqrt{3}-\sqrt{2}-\sqrt{7})=3-\sqrt{6}-\sqrt{21}-\sqrt{6}+2+\sqrt{14}+\sqrt{21}-\sqrt{14}-7=\\\\=3+2-7-2\sqrt{6}=-2-2\sqrt{6}\\\\lub\\\\(\sqrt{3}-\sqrt{2}+\sqrt{7})(\sqrt{3}-\sqrt{2}-\sqrt{7})=(\sqrt{3}-\sqrt{2})^2-(\sqrt{7})^2=\\\\=(\sqrt{3})^2-2\cdot\sqrt{3}\cdot\sqrt{2}+(\sqrt{2})^2-7=3-2\sqrt{6}+2-7=-2-2\sqrt{6}[/tex]
