[tex]\dfrac{x+5}{x-2}=\dfrac{x+1}{x}\qquad(x\not=2 \wedge x\not=0)\\\\x(x+5)=(x+1)(x-2)\\x^2+5x=x^2-2x+x-2\\6x=-2\\x=-\dfrac{2}{6}=-\dfrac{1}{3}[/tex]
