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[tex]\frac{5\sqrt8-2\sqrt{72}}{\sqrt2}=\frac{5\sqrt{4\cdot2}-2\sqrt{36\cdot2}}{\sqrt2}=\frac{5\sqrt{2^2\cdot2}-2\sqrt{6^2\cdot2}}{\sqrt2}=\\\\=\frac{5\cdot2\sqrt2-2\cdot6\sqrt2}{\sqrt2}=\frac{10\sqrt2-12\sqrt2}{\sqrt2}=\frac{-2\sqrt2}{\sqrt2}=\boxed{-2}[/tex]
