Odpowiedź:
a) C3H4 +HCl ---> C3H5Cl
b) 2CH3-CH2-CH2Br + 2Na--> CH3-CH2-CH2-CH2-CH2-CH3 +2NaBr
c) CH3COONa +NaOH-->CH4 + Na2CO3
d) C4H7OH + AL2O3/T ---> C4H6 +H2O
e) C6H12 + 9O2--> 6CO2 + 6H2O
f) CH3 CH3 CH3
I I I
CH3- C = CH +H2O-->CH3-C - CH2
I I
CH3 OH
g) H2C CH2 H3C CH2
\\ / \ \ / \
C CH3 +H2 --> CH CH3
I I
CH3 CH3
