[tex]-3x^{2}-5x + 1 = 0 \ \ /\cdot(-1)\\\\3x^{2}+5x-1 = 0\\\\a = 3, \ b = 5, \ c = -1\\\\\Delta = b^{2}-4ac = 5^{2}-4\cdot3\cdot(-1) = 25+12 = 37\\\\\sqrt{\Delta} = \sqrt{37}\\\\x_1 = \frac{-b-\sqrt{\Delta}}{2a} = \frac{-5-\sqrt{37}}{2\cdot3} = \frac{-5-\sqrt{37}}{6}\\\\x_2 = \frac{-b+\sqrt{\Delta}}{2a} = \frac{-5+\sqrt{37}}{6}[/tex]
