Obliczenia
[tex]\frac{8^3}{16^2}=\frac{(2^3)^3}{(2^4)^2}=\frac{2^{3\cdot3}}{2^{4\cdot2}}=\frac{2^9}{2^8}=2^{9-8}=\boxed{2^1}\\\\4^{10}:2^7=(2^2)^{10}:2^7=2^{2\cdot10}:2^7=2^{20}:2^7=2^{20-7}=\boxed{2^{13}}\\\\\frac{2\cdot16^3}{8^4}=\frac{2\cdot(2^4)^3}{(2^3)^4}=\frac{2\cdot2^{4\cdot3}}{2^{3\cdot4}}=\frac{2\cdot2^{12}}{2^{12}}=\frac{2^{1+12}}{2^{12}}=\frac{2^{13}}{2^{12}}=2^{13-12}=\boxed{2^1}[/tex]
