👤
Rozwiązane

ulamki podziel,pomnoz, odejmij

Ulamki Podzielpomnoz Odejmij class=

Odpowiedź :

LUBIEPLACKI1PLON

Odpowiedź:

  1. [tex]3 \frac{7}{35} - 1 \frac{5}{35} = 2 \frac{2}{35} [/tex]
  2. [tex]3 \frac{5}{7} [/tex]
  3. [tex]5 \frac{5}{40} - 1 \frac{4}{40} = 4 \frac{1}{40} [/tex]
  4. [tex] \frac{16}{5} \div \frac{6}{4} = \frac{16}{5} \times \frac{4}{6} = \frac{32}{15} = 2 \frac{2}{15} [/tex]
  5. [tex] \frac{7}{2} \times \frac{1}{8} = \frac{7}{16} [/tex]
  6. [tex] \frac{5}{4} \times \frac{2}{1} = \frac{10}{4} = 2 \frac{2}{4} = 2 \frac{1}{2} [/tex]

nie jestem pewny czy w 4 jest 1 2/4 czy 1 3/4 gdyby w 4 było 1 3/4 to:

[tex] \frac{16}{5} \div \frac{7}{4} = \frac{16}{5} \times \frac{4}{7} = \frac{64}{35} = 1 \frac{29}{35} [/tex]

ASTRAYSPIRIT2308ON

Od 1) do 3)

[tex]3\frac{1}{5}-1\frac{1}{7}=3\frac{7}{35}-1\frac{5}{35}=2\frac{2}{35}\\\\5-1\frac{2}{7}=4\frac{7}{7}-1\frac{2}{7}=3\frac{5}{7}\\\\5\frac{1}{8}-1\frac{1}{10}=5\frac{5}{40}-1\frac{4}{40}=4\frac{1}{40}[/tex]

Od 4) do 6)

[tex]3\frac{1}{5}:1\frac{3}{4}=\frac{16}{5}:\frac{7}{4}=\frac{16}{5}\cdot\frac{4}{7}=\frac{64}{35}=1\frac{29}{35}\\\\3\frac{1}{2}\cdot\frac{1}{8}=\frac{7}{2}\cdot\frac{1}{8}=\frac{7}{16}\\\\1\frac{1}{4}:\frac{1}{2}=\frac{5}{4}\cdot2=\frac{5}{2}=2\frac{1}{2}[/tex]

On Studier: Inne Pytanie