Z twierdzenia Pitagorasa:
[tex]2^{2}+2^{2} = y^{2}\\\\4+4 = y^{2}\\\\y^{2} = 8 = 4\cdot2\\\\y = 2\sqrt{2}\\\\\\x^{2}+(\frac{y}{2})^{2}=2^{2}\\\\x^{2}+(\frac{2\sqrt{2}}{2})^{2} = 2^{2}\\\\x^{2}+(\sqrt{2})^{2} = 2^{2}\\\\x^{2}+2=4\\\\x^{2} = 4-2 = 2\\\\x = \sqrt{2}\\\\\\Obw = 2x+2y = 2(x+y)\\\\Obw = 2(2\sqrt{2}+\sqrt{2}) = 2\cdot3\sqrt{2}=6\sqrt{2}[/tex]
