[tex]x^3-\sqrt3x+3\sqrt3-3=0\\x^3+3\sqrt3-\sqrt3x-3=0\\(x+\sqrt3)(x^2-\sqrt3x+3)-\sqrt3(x+\sqrt3)=0\\(x+\sqrt3)(x^2-\sqrt3x+3-\sqrt3)=0\\\\x+\sqrt3=0\\x=-\sqrt3\\\\x^2-\sqrt3x+3-\sqrt3=0\\\Delta=(-\sqrt3)^2-4\cdot1\cdot(3-\sqrt3)=3-12+4\sqrt3=-9+4\sqrt3\\\Delta<0 \Rightarrow x\in\emptyset[/tex]
Ostatecznie zatem [tex]x=-\sqrt3[/tex].
