Odpowiedź:
[tex]A.\ \ (x-2y)-(4x+y)-(y-x)=x-2y-4x-y-y+x=-2x-4y\\\\B.\ \ -3(1-2y)+\frac{1}{2}(6-12y)=-3+6y+3-6y=-3+3+6y-6y=0\\\\C.\ \ -5(2x+3)-3(5-3x)=-10x-15-15+9x=-x-30\\\\D.\ \ \frac{2x+1}{6}-\frac{1-x}{3}=\frac{2x+1}{6}-\frac{2(1-x)}{6}=\frac{2x+1}{6}-\frac{2-2x}{6}=\frac{2x+1-(2-2x)}{6}=\\\\=\frac{2x+1-2+2x}{6}=\frac{4x-1}{6}[/tex]
[tex]E.\ \ 4(-2x+0,5)-\frac{2}{3}(-6x+15)=-8x+2+4x-10=-4x-8\\\\F.\ \ -(x-2)-4(\frac{1}{2}-x)=-x+2-2+4x=3x\\\\G.\ \ 2x(-3x+4)-5-x(7-2x)=-6x^2+8x-5-7x+2x^2=-4x^2+x-5[/tex]
