Odpowiedź:
a)[tex]4^{\frac{3}{2} }}=\sqrt{4^3} =\sqrt{64} =8[/tex]
b)[tex]27^{\frac{2}{3} }=(\sqrt[3]{27})^2 =3^2=9[/tex]
c)[tex]8^{\frac{4}{3} }=(\sqrt[3]{8} )^4=2^4=16[/tex]
d)[tex]32^{\frac{3}{5} }=(\sqrt[5]{32})^3 =2^3=8[/tex]
e)[tex]81^{1,5}}=81^{\frac{3}{2}}=( \sqrt{81} )^3=9^3=729[/tex]
f)[tex]4^{2,5}}=4^{\frac{5}{2} }=(\sqrt{4})^5=2^5=32[/tex]
g)[tex]125^{-\frac{2}{3} }=(\frac{1}{125} )^{\frac{2}{3} }=(\sqrt[3]{\frac{1}{125} } )^2=(\frac{1}{5})^2=\frac{1}{25}[/tex]
h)[tex](\frac{1}{81})^{-\frac{3}{4} }=81^{\frac{3}{4} }=(\sqrt[4]{81} )^3=3^3=27[/tex]
i)[tex](\frac{1}{4} )^{-2,5}}=4^{\frac{5}{2} }=(\sqrt{4} )^5=2^5=32[/tex]
j)[tex](\frac{8}{27} )^{-\frac{2}{3}}=(\frac{27}{8} )^\frac{2}{3} }=(\sqrt[3]{\frac{27}{8} } )^2=(\frac{3}{2})^2=\frac{9}{4} =2\frac{1}{4}[/tex]
Szczegółowe wyjaśnienie:
