Odpowiedź :
[tex]x+\dfrac{1}{x}=7\\\\\left(x+\dfrac{1}{x}\right)^2=49\\\\x^2+2+\left(\dfrac{1}{x}\right)^2=49\\\\x^2+\left(\dfrac{1}{x}\right)^2=47[/tex]
[tex]x+\dfrac{1}{x}=7\\\\\left(x+\dfrac{1}{x}\right)^2=49\\\\x^2+2+\left(\dfrac{1}{x}\right)^2=49\\\\x^2+\left(\dfrac{1}{x}\right)^2=47[/tex]