Odpowiedź:
[tex]1.\ \ \dfrac{\sqrt{50}+\sqrt{72}}{\sqrt{2}}=\dfrac{\sqrt{25\cdot2}+\sqrt{36\cdot2}}{\sqrt{2}}=\dfrac{5\sqrt{2}+6\sqrt{2}}{\sqrt{2}}=\dfrac{11\sqrt{2}}{\sqrt{2}}=11\\\\\\2.\ \ \dfrac{\sqrt{48}+\sqrt{75}}{\sqrt{27}}=\dfrac{\sqrt{16\cdot3}+\sqrt{25\cdot3}}{\sqrt{9\cdot3}}=\dfrac{4\sqrt{3}+5\sqrt{3}}{3\sqrt{3}}=\dfrac{9\sqrt{3}}{3\sqrt{3}}=\dfrac{9}{3}=3[/tex]
[tex]3.\ \ \dfrac{\sqrt{32}+\sqrt{2}}{\sqrt{2}}=\dfrac{\sqrt{16\cdot2}+\sqrt{2}}{\sqrt{2}}=\dfrac{4\sqrt{2}+\sqrt{2}}{\sqrt{2}}=\dfrac{5\sqrt{2}}{\sqrt{2}}=5[/tex]
