Odpowiedź:
[tex]\sqrt{2}x^{2}+2\sqrt{3}x=-\sqrt{2}\\\sqrt{2}x^{2}+2\sqrt{3}x+\sqrt{2}=0\\[/tex]
Δ = [tex]12-4*2=4[/tex]
[tex]x_{1}=\frac{-2\sqrt{3}-2}{2\sqrt{2}} =\frac{-\sqrt{3}-1}{\sqrt{2}}=\frac{-\sqrt{6}-\sqrt{2}}{2}\\x_{2}=\frac{-2\sqrt{3}+2}{2\sqrt{2}} =\frac{-\sqrt{3}+1}{\sqrt{2}}=\frac{-\sqrt{6}+\sqrt{2}}{2}[/tex]
Szczegółowe wyjaśnienie:
