[tex]e)[(-\frac{2}{3} )^2:\frac{8}{9} ]^2-(\frac{3}{4} -1\frac{1}{8} )=[\frac{4}{9} *\frac{9}{8} ]^2-(\frac{6}{8} -\frac{9}{8} )=(\frac{1}{2} )^2-(-\frac{3}{8} )=\frac{1}{4} +\frac{3}{8} =\frac{2}{8} +\frac{3}{8} =\frac{5}{8} \\\\f)1,6*\frac{7}{16}-\frac{2,7}{3^3} } -\frac{5*0,7}{0,35} =\frac{8}{5} *\frac{7}{16} -\frac{\frac{27}{10} }{27} -10=\frac{7}{10} -\frac{27}{10} *\frac{1}{27} -10=\frac{7}{10} -\frac{1}{10} -10=\frac{6}{10} -\frac{100}{10} =-\frac{94}{10} =-9,4[/tex]
