[tex](5\frac{1\cdot5}{2\cdot5}+1\frac{2\cdot2}{5\cdot2})-(2\frac{1\cdot3}{4\cdot3}+1\frac{5\cdot2}{6\cdot2})=\\\\=(5\frac{5}{10}+1\frac{4}{10})-(2\frac{3}{12}+1\frac{10}{12})=\\\\=6\frac{9\cdot6}{10\cdot6}-4\frac{1\cdot5}{12\cdot5}=\\\\=6\frac{54}{60}-4\frac{5}{60}=\\\\=\boxed{2\frac{49}{60}}[/tex]
