a)
[tex]2^{3} = \underline{2\cdot2\cdot2}=8\\\\\\(\frac{3}{5})^{2} =\underline{ \frac{3}{5}\cdot\frac{3}{5}} = \frac{9}{25}\\\\\\(-1)^{5} = \underline{(-1)\cdot(-1)\cdot(-1)\cdot(-1)\cdot(-1)} =-1\\\\\\(-7)^{0} = 1[/tex]
b)
[tex](1\frac{2}{5})^{2} = \underline{(1\frac{2}{5})\cdot(1\frac{2}{5})}=(\frac{7}{5})^{2} =\frac{49}{25} = 1\frac{24}{25}[/tex]
[tex](-2\frac{1}{2})^{3} = \underline{(-2\frac{1}{2})\cdot(-2\frac{1}{2})\cdot(-2\frac{1}{2})}=(-\frac{5}{2})^{3} = \frac{125}{8} = 15\frac{5}{8}[/tex]
[tex]-1,2^{2} =\underline{ -1,2\cdot1,2} = -1,44[/tex]
[tex]-4^{3} =\underline{ -4\cdot4\cdot4}=-64[/tex]
