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[tex]3\cdot\dfrac{4}{5}=\dfrac{3\cdot4}{5}=\dfrac{12}{5}=\dfrac{10+2}{5}=\dfrac{10}{5}+\dfrac{2}{5}=2+\dfrac{2}{5}=\boxed2\dfrac{\boxed2}{\boxed5}\\\\\\5\cdot\dfrac{8}{9}=\dfrac{5\cdot8}{9}=\dfrac{40}{9}=\dfrac{36+4}{9}=\dfrac{36}{9}+\dfrac{4}{9}=4+\dfrac{4}{9}=\boxed4\dfrac{\boxed4}{\boxed9}\\\\\\8\cdot\dfrac{7}{11}=\dfrac{8\cdot7}{11}=\dfrac{56}{11}=\dfrac{55+1}{11}=\dfrac{55}{11}+\dfrac{1}{11}=5+\dfrac{1}{11}=\boxed5\dfrac{\boxed1}{\boxed{11}}[/tex]
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