Rozwiązanie:
[tex]a)[/tex]
[tex]P=\int\limits^6_0 {(-\frac{1}{6}x+3-\frac{2}{3}x+2 )} \, dx =\int\limits^6_0 {(-\frac{5}{6}x+5 )} \, dx =[-\frac{5x^{2}}{12}+5x ]^{6}_{0}=-\frac{5 \cdot 36}{12} +30=15[/tex]
[tex]b)[/tex]
[tex]P=\int\limits^6_0 ({\frac{1}{2}x+\frac{5}{2}-\frac{1}{2}x+\frac{3}{2}) } \, dx =\int\limits^6_0 {4} \, dx =[4x]^{6}_{0}=24[/tex]
