zad. 1
a) 20 - 2 * 6 = 8cm
B
b) 3 * 2 = 6cm - dłuższa przekątna
[tex] \frac{3 \times 6}{2} = 9cm {}^{2} [/tex]
B
zad. 2
a) 180° - 35° - 30° = 115° B
b) 180° - 105° - 25° = 50° C
zad. 3
a) P = a * h
20 = 4 * h
h = 5
A1
b)
[tex]P = \frac{e \times f}{2} [/tex]
[tex]40 = \frac{e \times 4}{2} [/tex]
2e = 40
e = 20
B2
zad. 4
I. P
II. F
III. P
IV. F
zad. 5
b) trójkąt równoramienny
c) 180° - 2 * 35° = 110°
zad. 6
a)
[tex]P = \frac{a \times h}{2} [/tex]
[tex]P = \frac{8 \times 3}{2} = \frac{24}{2} = 12cm {}^{2} [/tex]
b)
[tex]P = \frac{e \times f}{2} [/tex]
[tex]P = \frac{4 \times 4}{2} = 8cm {}^{2} [/tex]
zad. 7
1,4m = 140cm
1m = 100cm
[tex]P = \frac{(a + b) \times h}{2} [/tex]
[tex]P = \frac{(140 + 60) \times 60}{2} = 200 \times 30 = 6000cm {}^{2} [/tex]
