[tex]C_p=\frac{m_s}{m_r}\cdot100\%\\\\m_s\rightarrow masa \ substancji\\\\m_r\rightarrow masa \ roztworu \ (substancji+rozpuszczalnika)\\\\V_r=1500 \ cm^3\\\\d_r=1,25 \ \frac{g}{cm^3}\\\\m_r=V_r\cdot d_r=1500 \ cm^3\cdot1,25 \ \frac{g}{cm^3}=1875 \ g\\\\\frac{m_s}{1875 \ g}\cdot100\%=6\% \ \ |:100\%\\\\\frac{m_s}{1875 \ g}=0,06 \ \ |\cdot1875 \ g\\\\m_s=\underline{112,5 \ g \ soli}\\\\1875 \ g-112,5 \ g=\underline{1762,5 \ g \ wody}[/tex]
