👤
EDWARDKALIUKON
Rozwiązane

oblicz pole kwadratu o podanej długości boku
7dm,
10m,
8mm,
13dm,
1,2m,
25dm 5cm.​

Odpowiedź :

Odpowiedź:

1) 7*7= 49dm^2

2) 10*10=100 m^2

3) 8*8=64mm^2

4) 13*13 = 169dm^2

5) 1,2*1, 2=1, 44 m^2

6) 25*25=625dm^2

7) 5*5=25cm^2

MAROKESSSON

Odpowiedź:

49 [tex]dm^{2}[/tex], 100 [tex]m^{2}[/tex], 64 [tex]mm^{2}[/tex], 169[tex]dm^{2}[/tex], 1,44 [tex]m^{2}[/tex], 625 [tex]dm^{2}[/tex], 25 [tex]cm^{2}[/tex]

Szczegółowe wyjaśnienie:

P = a * a

[tex]P_{1}[/tex] = 7dm *7dm = 49 [tex]dm^{2}[/tex]

[tex]P_{2}[/tex] = 10m * 10m = 100 [tex]m^{2}[/tex]

[tex]P_{3}[/tex] = 8mm * 8mm = 64 [tex]mm^{2}[/tex]

[tex]P_{4}[/tex] = 13dm * 13dm =  169[tex]dm^{2}[/tex]

[tex]P_{5}[/tex] = 1,2m * 1,2 m = 1,44 [tex]m^{2}[/tex]

[tex]P_{6}[/tex] = 25dm * 25dm = 625 [tex]dm^{2}[/tex]

[tex]P_{7}[/tex] = 5cm * 5cm = 25 [tex]cm^{2}[/tex]

On Studier: Inne Pytanie